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in Mathematics by (71.5k points)

Find the equation of the circle having the lines x² + 2xy + 3x + 6y = 0 as its normals and having size just sufficient to contain the circle x (x - 4) + y (y - 3) = 0.

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x² + 2xy + 3x + 6y = 0 

x(x + 3) + 2y (x + 3) = 0 

(x + 3) (x + 2y) = 0 

normal point of intersection is the (– 3 , 3/2) 

size of the circle is such that it just contain the circle x(x – 4) + y (y – 3) = 0 

radius of circle be r 

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