Question

For a reaction A_(g) ⇋ B_(g) if initial pressure at 300^oC is 1 atm and its K_p is 4, Then calculate P_B at equilibrium state.

Answer 1

Given,

T = 300^oC

P_A = 1 atm

K_p = 4

The reaction is A_(g) ⇋ B_(g)

K_p = [P_B]/[P_A] ---> [P_B] = K_p x [P_A]

= 4 x 1 atm

= 4 atm

Total pressure = 4 atm + 1 atm = 5 atm

P_B 1 atm x 4/5 = 4/5 atm