Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
36.4k views
in Chemistry by (70.0k points)

Dissolving 120 g of a compound of (mol. wt. 60) in 1000 g of water gave a solution of density 1.12 g/mL. The molarity of the solution is: 

(a) 1.00 M 

(b) 2.00 M 

(c) 2.50 M 

(d) 4.00 M

1 Answer

+2 votes
by (74.3k points)
selected by
 
Best answer

Correct option: (b) 2.00 M

Explanation:

Given 

mass of solute (w) = 120 g 

mass of solvent (w) = 1000 g 

Mol. mass of solute = 60 g 

density of solution = 1.12 g/ mL 

From the given data, 

Mass of solution = 1000 + 120 = 1120 g

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...