1 mole of N2 H4 loses 10 mole of electrons and gets converted to a new compound X. Assuming that all the nitrogenation is

1 mole of N₂ H₄ loses 10 mole of electrons and gets converted to a new compound X. Assuming that all the nitrogenation is present in X, then oxidation state of N in the new compound X is

(1) − 3

(2) − 2

(3) + 3

(4) + 4

1 mole of N2 H4 loses 10 mole of electrons and gets converted to a new compound X. Assuming that all the nitrogenation is

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