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in Physics by (74.3k points)

A particle performing S.H.M. undergoes displacement of A/2  (where A = amplitude of S.H.M.) in one second. At t = 0 the particle was located at either extreme position or mean position. The time period of S.H.M. can be : (consider all possible cases)

(A) 12s 

(B) 2.4 

(C) 6s 

(D) 1.2s 

1 Answer

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Best answer

Correct option: (A, B, C, D)

Explanation:

It T be the time period ; time to go from O to Q is T/12 and from M to P is T/6

The displacement is A/2  when particle goes from O to Q, from O to N to Q, from O to N to O to P, and so on 

Hence possible time period T is

similarly displacement is A/2  when particle goes from M to P or M to N to P Hence the possible time period T is 

T = 1 × 6 = 6 s or T = 6x1 /5 s = 1.2 s

Ans. T = 1.2 s, 6s, 2.4s, 12s

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