Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
7.8k views
in Mathematics by (30 points)
recategorized by

Find the points on the curve y = x3 – 2x2 – x at which the tangent lines are parallel to the line y = 3x – 2.

Please log in or register to answer this question.

1 Answer

0 votes
by (323k points)

Let P(x1, y1) be the required point. The given curve is

Since the tangent at (x1, y1) is parallel to the line y = 3x - 2

Slope of the tangent at (x1, y1) = slope of the line, y = 3x - 2

Since (x1, y1) lies on the curve(i). Therefore

No related questions found

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...