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0 votes
27.7k views
in Physics by (69.2k points)

A force vector F = ( 3i 4j ) N acts on a 2 kg movable object that moves from an initial position vector d ( - 3i - 2j ) m to a final position  vector d = (5i + 4j)m in 6 s. The average power delivered by the force during the interval is equal to :

(A) 8 watt

(B) 50/6 Watt

(C) 15 watt

(D) 50/3 watt.

1 Answer

+1 vote
by (69.8k points)
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Best answer

Correct option: (A) 8 watt

Explanation:

Wavelength and velocity are medium dependent. Final amplitude is decided by the superposition of individual amplitudes.

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