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in Physics by (69.2k points)

A block of mass 10 kg is released on a fixed wedge inside a cart which is moved with constant velocity 10 m/s towards right. Take initial velocity of block with respect to cart zero. Then work done by normal reaction (with respect to ground )on block in two seconds will be: (g = 10 m/s2 ).

(A) zero 

(B) 960 J 

(C) 1200 J 

(D) none of these

1 Answer

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Best answer

Correct option: (B) 960 J

Explanation:

Because the acceleration of wedge is zero, the normal reaction exerted by wedge on block is N = mg cos 37°. 

The acceleration of the block is g sin 37° along the incline and initial velocity of the block is v = 10 m/s horizontally towards right as shown in figure. 

The component of velocity of the block normal to the incline is v sin 37°. Hence the displacement of the block normal to the incline in t = 2 second is 

S = v sin 37° × 2 = 10 × 3/5 × 2 = 12 m.

∴ The work done by normal reaction

W = mg cos 37° S = 100 x 4/5  × 12 = 960 J

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