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The oxidation state of Cr in [Cr(NH3)4Cl2]^+ is

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The oxidation state of Cr in [Cr(NH3)4Cl2]+ is
(a) +3 

(b) +2

(c) +1 

(d) 0

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1 Answer

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Best answer

(a) : Let the oxidation state of Cr in
[Cr(NH3)4Cl2]+ = x
x + 4(0) + 2(–1) = +1
x – 2 = +1 or, x = +1 + 2 = +3.

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