Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.9k views
in Physics by (79.9k points)

A car is moving on a plane inclined at 30º to the horizontal with an acceleration of 9.8 m/s2 parallel to the plane upward. A bob is suspended by a string from the roof. The angle in degrees which the string makes with the vertical is : (Assume that the bob does not move relative to car) [g = 9.8 m/s2 ]

(A) 20º 

(B) 30º 

(C) 45º 

(D) 60º

1 Answer

+1 vote
by (71.7k points)
selected by
 
Best answer

Correct option (B) 30º

Explanation: 

From frame of car, the effective acceleration (geff) due to gravity shall be measured as shown in figure. Hence geff makes an angle 30° with vertical direction (down wards). Since the string aligns with direction of geff in equilibrium, the required angle is = 30°

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...