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If fog(x) = 1 - x,  x  R and fof(x) = 1+ sin(f(x)),  x  R, then

(A)  f(0) = 1

(B) f(π) = 1

(C) f(x) is periodic

(D) f(x)  0,  x  R

1 Answer

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Best answer

Correct option (A)(B)(C)(D)


fof(g(x)) = 1 + sin(fog(x))

 f(1 - x) = 1 + sin(1 - x)

⇒ f(x) = 1 + sinx

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