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asked ago in Physics by (9.1k points)

Two particles moving parallel to the x-axis perform SHM with same amplitude (A) and frequency (f). At  a certain instant they are found at distance A / √2 from the mean position on opposite sides such that their velocties are in the same direction. Then the phase difference between their SHMs is :

(A) 90° 

(B) 120° 

(C) 180° 

(D) 270° 

1 Answer

+1 vote
answered ago by (10.6k points)
selected ago by
 
Best answer

Correct option: (A) 90°

Explanation:

Phase difference ϕ = 2θ 

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