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asked ago in Physics by (69.7k points)

The electric field associated with a light wave is given by E = E0 sin [1.57×107 m–1(ct–x)]. This light is used to emit photoelectron from a surface having a work function of 2.1 eV. The stopping potential is 

(1) 0.1 volt 

(2) 1 volt 

(3) 11 volt

(4) 1.1 volt

1 Answer

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answered ago by (36.7k points)
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Best answer

Correct option : (2) 1 volt

Explanation : 

The equation of a harmonic wave is given by E = E0 sin 2π/λ(vt - x)

The electric field associated with incident light is given by E0 sin 1.57 x 107 ms-1(ct - x) has the same form as of a harmonic wave. 

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