Join Sarthaks eConnect Today - Largest Online Education Community!
0 votes
asked in Physics by (79.2k points)

A sphere P(emissivity=1) of radius 2R and and another sphere Q(emissivity =1/2) of radius R are placed in vacuum at some distance.There are no other objects. The temperature of the sphere Q is maintained at 200K by the means of a heater. A fraction 1/32 of the power emitted by the sphere Q falls on the sphere P. If the equilibrium temperature of the sphere P is 10 T, find the value of T.

1 Answer

+1 vote
answered by (70.9k points)
selected by
Best answer

In equilibrium, power released= power absorbed\

Happy Diwali Wishes

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon