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asked ago in Physics by (9.1k points)

The angle of a prism is 'A'. One of its refracting surfaces is silvered. Light rays falling at an angle of incidence 2A on the first surface returns back through the same path after suffering reflection at the silvered surface. The refractive index μ, of the prism is :

(A) 2sin A 

(B) 2 cos A 

(C) 1 / 2 cosA

(D) tan A

1 Answer

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answered ago by (10.6k points)
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Best answer

Correct option: (B) 2 cos A


To retrace its path light rays should fall normally on the reflecting surface. So

r2 = 0 ⇒ r1 = A – r2  ⇒ r1 = A

Now applying snell rule between incident ray and refracted ray.

(A) sin (2A) = n sin (A) ⇒ 2 sin A cos A = n sin A

⇒ n = 2 cos A

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