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In the circuit shown in the figure the capacitor is initially uncharged

At the instant mentioned in the previous question S1 is opened and S2 is closed simultaneously. Taking this instant is t = 0, the charge on the capacitor as a function of time is best represented by :

(A) q = (4.4 e–t )mC

(B) q = (10 + 5.6 e–t )mC 

(C) q = (10 – 5.6 e–t )mC

(D) q = (5.6 e–t – 1.2)mC

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Correct option (C) q = (10 – 5.6 e–t )mC


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