It may be assumed that the average kinetic energy, of a free particle, at a temperature T, equals 3/2 kT (k = Boltzmann constant). The (average) deBroglie wavelength, associated with a free electron (mass = m) at a temperature T1, equals the (average) deBroglie wavelength, associated with a free α–particle (mass = M) at a temperature T2. Similarly, the deBroglie wavelength, associated with an electron, accelerated through a potential V1, equals the deBroglie wavelength, associated with an α–particle, accelerated through a potential V2. The temperatures, (T1 and T2) and the potentials, (V1 and V2), would then be related as
(1) T2V1 = 2T1V2
(2) 2T2V1 = T1V2
(3) 2T2V2 = T1V1
(4) T2V2 = 2T1V1
