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in Physics by (70.7k points)

For a constant intensity of the incident radiation, the graphs between the frequency (v) of the incident, and the magnitude (VS) of the corresponding stopping potential, for different photosensitive surfaces, have the form shown here. 

Let the intercepts, of these graphs, on the ‘potential’ and the ‘frequency’ axes, be denoted by yi and xi (i = 1, 2, 3,.....n) for different photosensitive surfaces. The graph, between yi and xi, would then have the form of the graph, labelled as graph 

(1) A 

(2) B

(3) C 

(4) D

1 Answer

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Best answer

Correct option : (2) B

Explanation : 

As per Einstein’s photoelectric equation, we have

(e = magnitude of electronic charge) 

∴ Intercept on the v–axis (= v0) is given by (taking VS = 0) 0 = hv0 – W

Similarly, the intercept on the VS axis (= VSO, say) is given by (taking v = 0)

eVSO = 0 – W

or VSO = -W/e

∴ The relation between (yi) and (xi) is -eyi = hxi (= W, each)

The required graph is therefore, a straight line passing through the origin and having a negative slope (slope =(-h/e). 

These requirement are met only by the graph labelled as graph B.

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