Correct option : (2) B
Explanation :
As per Einstein’s photoelectric equation, we have
(e = magnitude of electronic charge)
∴ Intercept on the v–axis (= v0) is given by (taking VS = 0) 0 = hv0 – W
Similarly, the intercept on the VS axis (= VSO, say) is given by (taking v = 0)
eVSO = 0 – W
or VSO = -W/e
∴ The relation between (yi) and (xi) is -eyi = hxi (= W, each)
The required graph is therefore, a straight line passing through the origin and having a negative slope (slope =(-h/e).
These requirement are met only by the graph labelled as graph B.