Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
7.7k views
in Mathematics by (69.4k points)
edited by

Let A = {x1 , x2 ,......, x7 } and B = {y1 , y2 , y3 } be two sets containing seven and three distinct elements respectively. Then the total number of functions f : A  B that are onto, if there exist exactly three elements x in A such that f(x) = 1/2 , is equal to :

(1)  14.7C3

(2)  16.7C3

(3)  14.7C2 

(4)  12.7C2 

1 Answer

+2 votes
by (64.1k points)
selected by
 
Best answer

Correct option  (1) 14.7C3

Explanation:

Number of onto function such that exactly three elements in x  A such that f(x) = 1/2  is equal to

= 7C3 .{24 – 2}

= 14.7C3

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...