Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
562 views
in Physics by (71.1k points)

In the photo disintegration equation for the neutron the reaction energy is 2.227 ± 0.003 MeV is

γ(hv) + 1H2 → 1H2  + 0n1 + 2.27 MeV

From the mass spectrometer the mass differences between the doublet 2 (1H2) and D (1H2) is 1.5380 ± 0.0021×10–2 amu. If the mass of hydrogen atom is 1.008145 ± 0.000003 amu. Then the mass of neutron is given by 

(1) 1.0089992 + 0.0000021 amu 

(2) 1.0089992 + 0.000003 amu 

(3) 1.0089992 + 0.000008 amu 

(4) 1.0089992 + 0.003 amu

1 Answer

+1 vote
by (70.7k points)
selected by
 
Best answer

Correct option : (2) 1.0089992 + 0.000003 amu

Explanation: 

The mass of neutron is given by

= –0015380 + 1.008145 – 0.002392 = 1.0089999 amu 

Errors: 

(i) Energy 2.27 ± 0.003 MeV equivalent of an error of 0.000003 

(ii) Doublet error = ± 0.0000021 amu 

(iii) Hydrogen atom = 0.00003 amu 

Total maximum error is ± 0.000008 amu 

Hence the mass of neutron is 1.0089992 ± 0.000008 amu

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...