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in Physics by (69.2k points)

A uniform disc of mass m and radius R is free to rotate about its fixed horizontal axis without friction. There is sufficient friction between the in extensible light string and disc to prevent slipping of string over disc. At the shown instant extension in light spring is 3 mg / K the block is released, where m is mass of block, g is acceleration due to gravity and K is spring constant.

(A) Acceleration of block just after it is released is 4g / 3

(B) Tension in the string continuously increases till extension in the spring reaches maximum value.

(C) maximum speed of block is  g √(6m / K)

(D) After some time string will slack

1 Answer

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by (69.7k points)
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Best answer

Correct option: (A, D)

Explanation;

For disc, from torque equation

By application of Newton's second law on block we get, 

T – mg = ma .... (2)

where a = R ..... (3)

solving a = 4g / 3

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