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The oxidation state of sulphur in H2SO5 and of chromium in K2Cr2O7 respectively is -

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The oxidation state of sulphur in H2SO5 and of chromium in K2Cr2O7 respectively is - 

(a) 8, 6 

(b) 4, 6 

(c) 8, 8 

(d) 6, 6

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Correct option: (d) 6, 6

Explanation:

Oxidation state of S = + 2 + 2 + 1 + 1 = + 6

K2Cr2O7 ⇒ +2 + 2x – 14 = 0 x = + 6

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