Question

In the circuit shown in Fig. V_i = 5V. V_BE = 0 and V_CE = 0. What is I_B and I_C ?

Answer 1

Correct option: (1)

Explanation: 

For base–emitter loop; using Kirchoff’s law

I_B R_B + V_BE = V_i 

where I_B is base current. Given V_BE = 0; RB = 2×10⁵Ω

∴ I_B ×2×10⁵ = 5

or I_B = 2.5×10^–5A = 25µA

For the collector–emitter loop; using Kirchoff’s law