(c) 300 % increase in power dissipated

As we know that if the current flowing through the resistor is I then

P_{1} = I^{2}R

If the current flowing through the resistor is increased by 100%

Then current = I + (I x 100/100 %) = 2I

Now power

P_{2} = (2I)^{2}R = 4I^{2}R

Change in percentage of power is (P_{2} - P_{1}) /( P_{1}) x 100% = (4I^{2}R - I^{2}R)/(I^{2}R) x 100%

= 300%