Sarthaks APP
+1 vote
96.7k views
in Physics by (51.2k points)
(a) 100 % (b) 200 %
(c) 300 % (d) 400 %

2 Answers

0 votes
by (258k points)
 
Best answer

Let the original value of current be I amp. 

+1 vote
by (258k points)

(c) 300 % increase in power dissipated

As we know that if the current flowing through the resistor is I then 
P1 = I2R
If the current flowing through the resistor is increased by 100%
Then current = I + (I x 100/100 %) = 2I
Now power
P2 = (2I)2R = 4I2R
Change in percentage of power is (P2 - P1) /( P1) x 100% = (4I2R - I2R)/(I2R) x 100%
= 300%

by (10 points)
How come 3o0 percentage
by (7.1k points)
See the solution.
Sarthaks APP

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...