(c) 300 % increase in power dissipated
As we know that if the current flowing through the resistor is I then
P1 = I2R
If the current flowing through the resistor is increased by 100%
Then current = I + (I x 100/100 %) = 2I
Now power
P2 = (2I)2R = 4I2R
Change in percentage of power is (P2 - P1) /( P1) x 100% = (4I2R - I2R)/(I2R) x 100%
= 300%