Correct option (B, D)
Explanation:
In case of free expansion under adiabatic conditions, change in internal energy ΔU = 0
∴ Internal energy and temperature will remain constant.
If volume is doubled, temperature will decrease as per equation
(ii). Further, molar heat capacity in process PVx = constant is
Since, molar heat capacity is positive, according to Q = nCΔT, Q will be negative if ΔT is negative. Or gas loses heat if temperature is decreasing.
Further, with increase in volume temperature will decrease.
As molar heat capacity is negative, Q will be positive if ΔT is negative. Or gas gains heat with decrease in temperature.
(D) T ∝ PV
In expansion from V1 to 2V1 , product of PV is increasing. Therefore, temperature will increase. Or ΔU = +ve. Further, in expansion work done is also positive.
Hence, Q = W + ΔU = +ve or, gas gains heat.