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+2 votes
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asked in Mathematics by (8k points)
Let a1,a2,a3.............  be terms of an AP. If (a1+a2+a3+a4...............ap)/(a1+a2+a3+a4................aq)=p^2/Q^2, THEN find the value of a6/a21.
commented by (14.7k points)
@Rahul, Please correct your question in p^2/Q^2

1 Answer

+1 vote
answered by (14.7k points)

Your question is a bit not clear.But what I understand showing you.

Given  a1,a2,a3.............  be terms of an AP

Let common difference is d

(a1+a2+a3+a4...............ap)/(a1+a2+a3+a4................aq)=p^2/Q^2

p/2[2a1 + (p-1)d] / q/2[2a1+(q-1)d] = P2/Q2

=> p[2a1 + (p-1)d] / q[2a1+(q-1)d] = P2/Q2  --------------------(1)

Now a6/a21 = a1 + (6-1)d / a+ (21-1)d

=> a6/a21 = a1 + 5d / a+ 20d  -------------(2)

Now find the ratio using equation (1) and (2)

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