Question

Find the complement of the following Boolean function : F1 = AB’ + C’D’

Answer 1

(AB’ + C’D’)’ = (AB’)’.(C’D’)’ (De Morgan’s first theorem)

= (A’ + B’’).(C’’ + D’’) (DeMorgan’s second theorem i.e., (A.B)’= A’+ B’)

= (A’ + B’).(C + D) ((X’)’= X)

Comments

Wrong ans
Correction should be done in 2nd line