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In perfectly inelastic collision between two bodies momentum remains constant and the bodies stick together. Angular frequency of a spring block system is ω = √K/m and maximum speed of particle is SHM is ωA, where A is the amplitude.

Two identical blocks P and Q have mass m each. They are attached to two identical springs initially unstretched. Now the left spring (along with P) is compressed by A/2 and the right spring (along with Q) is compressed by A. Both the blocks are released simultaneously. They collide perfectly inelastically. Initially time period of both the block was T. 

The time period of oscillation of combined mass is - 

(A) T/√2 

(B) √2T 

(C) T 

(D) T/2

 

1 Answer

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Best answer

Correct option (C) T

Explanation:

They will collide at their mean positions because time period of both are same and that is 2π√(M/KAfter collision combined mass is 2m and Keff = 2K. Hence, time period remains unchanged.

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