Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
6.1k views
in Computer by (69.4k points)

Convert the following expressions to canonical Product-of-Sum form

(a)  (A + C)(C + D)

(b)  (X + Y)(Y + Z)(X + Z) 

1 Answer

0 votes
by (61.3k points)
selected by
 
Best answer

(a)  (A + C)(C + D)

= (A + BB’ + C + DD’)(AA’ + BB’ + C + D)

= (A + B + C + D)(A + B’ + C + D’)(A + B + C + D)(A’ + B’ + C + D)

By removing duplicate terms we get canonical Product-of-Sum form:

(A + B + C + D)(A + B’ + C + D’)(A’ + B’ + C + D)

F = π(0, 5 , 12)

F = M0 + M5 + M12

(b) (X + Y)(Y + Z)(X + Z)

= (X + Y + ZZ’)(XX’ + Y + Z)(X + YY’ + Z)

= (X + Y + Z)(X + Y + Z’)(X + Y + Z)(X’ + Y + Z)(X + Y + Z)(X + Y’ + Z)

By removing duplicate terms we get canonical Product-of-Sum form:

(X + Y + Z)(X + Y + Z’)( X’ + Y + Z)( X + Y’ + Z)

F = π(0, 1 , 2, 4)

F = M0 + M1 + M2 + M4

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...