Question

A sample of AgCl was treated with 10 mL of 1.7 M Na₂CO₃ solution to give Ag₂CO₃. The remaining solution contained 0.0026 g of Cl^– per litre. Calculate solubility product of AgCl. K_sp(Ag2CO3) = 8.2 × 10^–12.

Answer 1

K_sp(AgCl) = [Ag⁺] [Cl^–] = (2.1963 × 10^–6) × (7.32 × 10^–5) = 1.61 × 10^–10.