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If solution of the equation 3cos^2 θ – 2√3 sinθ cosθ – 3 sin^2 θ = 0 are nπ + π/r and nπ +π /s then |r -s| =

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If solution of the equation 3cos2 θ – 2√3 sinθ cosθ – 3 sin2 θ = 0 are nπ + π/r and nπ +π /s then |r -s| =

(A) 3 

(B) 9 

(C) 7 

(D) 1

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Correct option (B) 9

Explanation: 

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