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in Mathematics by (63.7k points)

Find the square root of 1471369.

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In the given number, mark off the digits in pairs starting from the unit's digit. Each pair and the remaining one digit is called a period.

Now, 12 = 1. On subtracting, we get 0 as remainder.

Now, bring down the next period i.e., 47. 

Now, trial divisor is 1 x 2 = 2 and trial dividend is 47.

So, we take 22 as divisor and put 2 as quotient.

The remainder is 3. 

Next, we bring down the next period which is 13. 

Now, trial divisor is 12 x 2 = 24 and trial dividend is 313. So, we take 241 as dividend and 1 as quotient. The remainder is 72. 

Bring down the next period i.e., 69. 

Now, the trial divisor is 121 x 2 = 242 and the trial dividend is 7269. So, we take 3 as quotient and 2423 as divisor. The remainder is then zero. 

Hence, √1471369 = 1213.

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