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For a certain organ pipe, three successive resonance frequencies are observed at 425, 595 and 765 Hz, respectively. Taking the speed of sound in the air to be 340 metre per second, (i) explain whether the pipe is closed at one end or open at both the ends and (ii) determine the fundamental frequency and the length of the pipe.

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(i) Given ratio of successive frequencies = 425 : 595 : 765 

= 5 : 7 : 9. 

So, the harmonics are odd harmonics. Hence the pipe is closed at one end.

(ii) Fundamental frequency n is given by, n = 425/5 = 85

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