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in Physics by (79.8k points)

A stone tied to the end of a string which is 80 cm long is whirled in a horizontal circle with a constant speed. If the stone makes 14 revolutions in 25 s, what is the magnitude of centripetal acceleration? 

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Given: r = 80 cm = 0.80 m, n = 14/25 s−1 

To find: Centripetal acceleration (ar) 

Formula: Centripetal acceleration,

ar = rω2 

Calculation: From formula, 

 The magnitude of centripetal acceleration is 9.91 m/s2

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