There are 3 Pairs and 1 Octet that reduce as given below:
Pair-1(m0 + m1) reduces to u’v’w’
Pair-2(m12 + m13) reduces to uvw’
Pair-3(m10 + m14) reduces to uwz’
Octet(m1 + m3 + m5 + m7 + m9 + m11 + m13 + m15) reduces to z
Simplified Boolean expression for given K-map is F(u, v, w, z) = u’v’w’ + uvw’ + uwz’ + z