Question

Convert the following Boolean expression into its equivalent Canonical Product of Sum Form(POS) : A.B’.C + A’.B.C + A’.B.C’

Answer 1

Given A.B’.C + A’.B.C + A’.B.C’

(1 0 1) (0 1 1) (0 1 0)

= m₅ + m₃ + m₂ = ∑(2, 3, 5)

POS is equal to (excluding positions of minterms)

= π(0, 1, 4, 6, 7)

= M₀.M₁.M₄.M₆.M₇

= (A + B + C).(A + B + C’).(A' + B + C).(A’ + B’ +C).(A’ + B’ + C’)