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Convert the following Boolean expression into its equivalent Canonical Sum of Product Form(SOP).

(U’ + V’ + W’).(U + V’ + W’).(U + V + W)

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Given (U’ + V’ + W’).(U + V’ + W’).(U + V + W)

(1 + 1 + 1) (0 + 1 + 1) (0 + 0 + 0)

= M0.M3.M7

= π(0, 3, 7) 

SOP is equal to(excluding position of Maxterms)

= ∑(1, 2, 4, 5, 6)

= m1 + m2 + m4 + m5 + m6 

= U’V’W + U’VW’ + UV’W’ + UV’W + UVW’

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