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Reduce the following Boolean expression using K-map: F(A, B, C, D) = ∑(3, 4, 5, 6, 7, 13, 15) 

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There are 2 Pair and 1 Quad that reduce as given below:

Pair-1(m3 + m7) reduces to A’CD

Pair-2(m4 + m7) reduces to A’BD’

Quad(m1+ m5 + m9 + m13 ) reduces to BD

Simplified Boolean expression for given K-map is

F(A, B, C, D) = A’CD +’ A’BD’ + BD

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