Question

Reduce the following Boolean expression using K-map:

H(U, V, W, Z) = ∑(0, 1, 4, 5, 6, 7, 11, 12, 13, 14, 15)

Answer 1

There are 2 Pair and 1 Octet that reduce as given below:

Pair-1(m₀ + m₁) reduces to U’V’W’

Pair-2(m₁₁+ m₁₅) reduces to UWZ

Octet (m₄ + m₅ + m₆ + m₇ + m₁₂+ m₁₃ + m₁₄ + m₁₅) reduces to V

Simplified Boolean expression for given K-map is F(U, V, W, Z) = U’V’W’ +’ UWZ + V