Question

The solubility of CaF₂ in water at 18°C is 2.05 x 10^–4 mole per litre. Calculate its solubility product.

(a) 3.45 x 10¹¹ 

(b) 4.45 x 10^–11

(c) 3.45 x 10^–10 

(d) 3 x 10^–11

Answer 1

Correct option: (a) 3.45 x 10^–11

Explanation: 

CaF₂ ⇌ Ca²⁺ + 2F^– 

Since the solubility of CaF₂ in water is 2.05 x 10^–4