Fewpal
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(a) I2R (b) IR2 (c) VI (d) V2/R

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We know that electric power is given by P = VI … (i)
So, the option (c) is correct.
According to Ohm’s law, V = IR … (ii)
Now putting the value of V from (ii) in (i), we get
Power P = (IR) × I = I2R
So, the option (a) is correct.
Now putting the value of I from (ii) in (i), we get
Power P = V(V/R) = V2/R
So, the option (d) is correct.
Hence, the option (b) does not represent electrical power in a circuit.

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