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A bullet of mass 25 g is fired horizontally into a ballistic pendulum of mass 5.0 kg and gets embedded in it (figure 9 E14). If the centre of the pendulum rises by a distance of 10 cm, find the speed of the bullet.

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by (32.5k points)
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Mass of bullet = 25g = 0.025kg.
Mass of pendulum = 5kg.
The vertical displacement h = 10cm = 0.1m
Let it strike the pendulum with a velocity u.
Let the final velocity be v.

0 – (1/2) (M + m). V2 = – (M + m) g × h ⇒ u2/(201)2=2 × 10 × 0.1 = 2
⇒ u = 201 × 2 = 280 m/sec

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