Question

The pendulum bob has a speed of 3 m/s at its lowest position. The pendulum is 0.5 m long. The speed of the bob, when the length makes an angle of o 60° to the vertical will be …….m/sec(g = 10ms^-2)

Answer 1

K E. at the lowest position = 1/2 mv² = 1/2m x (3)² = 9/2 m.

When the length makes an angle θ (= 60°) to the vertical, the bob of the pendulum will have both K E. and P E. . If v is velocity of bob at this position and h is the height of the bob w.r.t. O . Then total energy of the bob E = 1/2mv² + mgh