The incorrect statement is
(A) p →q is logically equivalent to ~p ∨ q.
(B) If the truth-values of p, q r are T, F, T respectively, then the truth value of (p ∨ q) ∧ (q ∨ r) is T.
(C) ~(p ∨ q ∨ r) = ~p ∧ ~q ∧ ~r
(D) The truth-value of p ~ (p ∧ q) is always T.
