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Find the value of x which satisfies the relation Log10 3+log10 (4x+1)=log10 (x+1)+1

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Find the value of x which satisfies the relation 

Log10 3+log10 (4x+1)=log10 (x+1)+1

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log10 3+log10 (4x+1)=log10 (x+1)+1 

Log10 3+log10 (4x+1)=log10 (x+1)+log10 (x+1)+log10 10 

Log10 (3(4x+1))=log10 (10(x+1)) 

=3(4x+1)=10(x+1)=12x+3 

=10x+10 

=2x=7

x=7/2

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