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in Mathematics by (63.7k points)

The perimeters of two squares are 40 cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.

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Side of first square = (40/4) = 10 cm; 

Side of second square = (32/4)cm = 8 cm. 

Area of third square = [(10)2 - (8)2] cm2 = (100 - 64) cm2 = 36 cm2 .

Side of third square = (36)(1/2) cm = 6 cm. 

 Required perimeter = (6 x 4) cm = 24 cm

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