Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.5k views
in Physics by (64.1k points)

An open pipe is in resonance in 2nd harmonic with frequency f1 . Now one end of the tube is closed and frequency is increased to f2 such that the resonance again occurs in nth  harmonic. Choose the correct option

(a)  n= 3,f2 = 3/4f1

(b)  n= 3,f2 = 5/4f1

(a)  n = 5,f2 = 3/4f1

(d)  n = 5, f2 =  5/4 f1

1 Answer

0 votes
by (61.3k points)
selected by
 
Best answer

Correct option  (d)  n = 5, f2 =  5/4 f1

Explanation:

Initially, the pipe is open at both ends.

For second harmonic, λ = l

∴ Frequency f1 = v/λ = v/l

Finally, the pipe is closed at one end.

For  nth  harmonic λ = 4l/n where n is an odd number.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...