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A π-meson with a kinetic energy of 140MeV decays in flight into μ-meson and a neutrino. Calculate the maximum energy which (a) the μ-meson (b) the neutrino may have in the Laboratory system (Mass of π-meson = 140 MeV/c2, mass of μ-meson = 106 MeV/c, mass of neutrino = 0)

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γπ = 1 + Tπ/mπ = 1 + 140/140 = 2

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