Correct option (b) 4800 Å
Explanation:
If D is separation between sources and screen the fringe width is given as
β = λD/d
⇒ β/λ = D/d
where d = separation between virtual sources. If d and D are fixed, then
β1/λ 1 = β2/λ 2
In first case 20 fringes occupy 2 cm